Conditional probability: red and green balls

[sbacelar]

I may be wrong but I think $A and $B below should be changed like this:

$A = \{(R,G)\} => P(A) => \frac{3}{6}$
$B = \{(R,G),(R,B),(R,W)\} => P(B) = \frac{3}{6}$

I think this is wrong:

A = “I pick a red and a green ball”
B = “I pick a red ball”
P(A|B) is interpreted as the probability of picking a red and a green ball knowing that I already picked one red ball.
$A = \{(R,G),(R,B),(R,W)\} => P(A) = \frac{3}{6}$
$B = \{(R,G)\} => P(B) => \frac{3}{6}$