How to run block in the current shell?

[thevops]

I'd like to run block using the current shell without overwriting it since I use direnv.
I use Runme CLI.

I've found that when I set shellscript at the begging of the block then it works good, but every time I save the file in VSCode (with Runme extension) shellscript is replaced with sh and it's not working.

Current state

Block test1:

echo $PATH | tr ":" "\n"

Command: runme run --filename .runbooks/test.runme test1

On the output I got overwrited PATH. This is not what I have when I run echo $PATH in the current shell.

Expected state

Some switch or configuration that preserves shellscript option in file or a flag for Runme CLI that overwrites behavior.

[lalyos]

I found this comment in the code: https://github.com/stateful/runme/blob/main/internal/command/config.go#L45-L48

	// shellscripts
	// TODO(adamb): breaking change: shellscript was removed to indicate
	// that it should be executed as a file. Consider adding it back and
	// using attributes to decide how a code block should be executed.

But as a workaround you can write a shell function:

• which redirects runme run --dry-run output to a file .runme
• delete the first 5 lines (shebang and set)
• than executes the command in the same shell: source .runme

here is a poc

runme-here() {
  runme run "$@" --dry-run |& sed 1,5d > .runme
  source .runme
}

after that you just replace runme run with runme-here

# original command in a subshell
runme run  --filename .runbooks/test.runme test1 

# running dry-run output in the same shell
runme-here --filename .runbooks/test.runme test1