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itemtype="http://schema.org/Organization"><meta itemprop="name" content="Moorez"></span><header class="post-header"><h1 class="post-title" itemprop="name headline">蓝桥杯 李白喝酒</h1><div class="post-meta"><span class="post-time"><span class="post-meta-item-icon"><i class="fa fa-calendar-o"></i></span> <span class="post-meta-item-text">发表于</span> <time itemprop="dateCreated" datetime="2017-03-03T22:34:14+08:00" content="2017-03-03">2017-03-03</time></span> <span class="post-category"> | <span class="post-meta-item-icon"><i class="fa fa-folder-o"></i></span> <span class="post-meta-item-text">分类于</span> <span itemprop="about" itemscope itemtype="https://schema.org/Thing"><a href="/categories/c-c/" itemprop="url" rel="index"><span itemprop="name">c-c++</span></a></span></span> <span id="/蓝桥杯 李白喝酒！.html" class="leancloud_visitors" data-flag-title="蓝桥杯 李白喝酒"> | <span class="post-meta-item-icon"><i class="fa fa-eye"></i></span> <span class="post-meta-item-text">热度</span><span class="leancloud-visitors-count"></span> <span>℃</span></span><div class="post-wordcount"><span class="post-meta-divider">|</span><span class="post-meta-item-icon"><i class="fa fa-file-word-o"></i></span> <span class="post-meta-item-text">字数统计</span> <span title="字数统计">400 字</span> <span class="post-meta-divider">|</span><span class="post-meta-item-icon"><i class="fa fa-clock-o"></i></span> <span class="post-meta-item-text">阅读时长</span> <span title="阅读时长">2 分钟</span></div></div></header><div class="post-body" itemprop="articleBody"><h2 id="问题"><a href="#问题" class="headerlink" title="问题"></a>问题</h2><p>话说大诗人李白，一生好饮。幸好他从不开车。<br>一天，他提着酒壶，从家里出来，酒壶中有酒两斗。他边走边唱：</p><p>无事街上走，提壶去打酒。<br>逢店加一倍，遇花喝一斗。</p><p>这一路上，他一共遇到店 55 次，遇到花 1010 次，已知最后一次遇到的是花，他正好把酒喝光了。请你计算李白遇到店和花的次序，有多少种可能的方案。</p><a id="more"></a><h2 id="思路"><a href="#思路" class="headerlink" title="思路"></a>思路</h2><p>我们已知遇店 5 次，遇花 10 次，并且最后一次遇到花，正好把酒喝光。那么我们可以把店作为二进制中的 1，把花作为二进制中的 0，因为已经确定最后一次遇到的是花，所以我们需要判断枚举的结果是否刚好有 5个 1 和 9个 0。那么我们就枚举出 14 位二进制的所有可能并加以判断即可，判断思路为判断二进制是否有 9 个 0，5个 1，并且最终酒刚好剩 1 斗</p><h2 id="实现代码"><a href="#实现代码" class="headerlink" title="实现代码"></a>实现代码</h2><figure class="highlight c++"><table><tr><td class="gutter"><pre><div class="line">1</div><div class="line">2</div><div class="line">3</div><div class="line">4</div><div class="line">5</div><div class="line">6</div><div class="line">7</div><div class="line">8</div><div class="line">9</div><div class="line">10</div><div class="line">11</div><div class="line">12</div><div class="line">13</div><div class="line">14</div><div class="line">15</div><div class="line">16</div><div class="line">17</div><div class="line">18</div><div class="line">19</div><div class="line">20</div><div class="line">21</div><div class="line">22</div></pre></td><td class="code"><pre><div class="line"><span class="meta">#<span class="meta-keyword">include</span><span class="meta-string"><stdio.h></span></span></div><div class="line"><span class="function"><span class="keyword">int</span> <span class="title">main</span><span class="params">()</span></span>{</div><div class="line"> <span class="keyword">int</span> ans=<span class="number">0</span>;<span class="comment">//方案数</span></div><div class="line"> <span class="keyword">for</span> (<span class="keyword">int</span> i=<span class="number">0</span>; i<(<span class="number">1</span><<<span class="number">14</span>); i++) {</div><div class="line"> <span class="keyword">int</span> dian=<span class="number">0</span>;<span class="comment">//表示遇到店的次数</span></div><div class="line"> <span class="keyword">int</span> hua=<span class="number">0</span>;<span class="comment">//表示遇到话的次数</span></div><div class="line"> <span class="keyword">int</span> num=<span class="number">2</span>;<span class="comment">//初始酒壶有两斗</span></div><div class="line"> <span class="keyword">for</span> (<span class="keyword">int</span> j=<span class="number">0</span>;j<<span class="number">14</span> ;j++) {</div><div class="line"> <span class="keyword">if</span> (i&(<span class="number">1</span><<j)) {<span class="comment">//这里判断二进制i从右数第j+1为是否为1</span></div><div class="line"> dian++;<span class="comment">//遇到店，次数加1</span></div><div class="line"> num*=<span class="number">2</span>;<span class="comment">//加一倍</span></div><div class="line"> }<span class="keyword">else</span>{</div><div class="line"> hua++;<span class="comment">//遇到花，次数加1</span></div><div class="line"> num-=<span class="number">1</span>;<span class="comment">//喝一斗</span></div><div class="line"> }</div><div class="line"> }</div><div class="line"> <span class="keyword">if</span> (dian==<span class="number">5</span>&&hua==<span class="number">9</span>&&num==<span class="number">1</span>) {</div><div class="line"> ++ans;<span class="comment">//记录方法数</span></div><div class="line"> }</div><div class="line"> }</div><div class="line"> <span class="built_in">printf</span>(<span class="string">"%d\n"</span>,ans);</div><div class="line">}</div></pre></td></tr></table></figure></div><div><div><div style="text-align:center;color:#ccc;font-size:14px">-------------本文结束<i class="fa fa-paw"></i>感谢您的阅读-------------</div></div></div><div><div class="my_post_copyright"><script src="//cdn.bootcss.com/clipboard.js/1.5.10/clipboard.min.js"></script><script src="https://cdn.bootcss.com/jquery/2.0.0/jquery.min.js"></script><script src="https://unpkg.com/sweetalert/dist/sweetalert.min.js"></script><p><span>本文标题:</span><a href="/蓝桥杯 李白喝酒！.html">蓝桥杯 李白喝酒</a></p><p><span>文章作者:</span><a href="/" title="访问 shenzekun 的个人博客">shenzekun</a></p><p><span>发布时间:</span>2017年03月03日 - 22:34</p><p><span>最后更新:</span>2018年10月21日 - 20:51</p><p><span>原始链接:</span><a href="/蓝桥杯 李白喝酒！.html" title="蓝桥杯 李白喝酒">http://www.shenzekun.cn/蓝桥杯 李白喝酒！.html</a><span class="copy-path" title="点击复制文章链接"><i class="fa fa-clipboard" data-clipboard-text="http://www.shenzekun.cn/蓝桥杯 李白喝酒！.html" aria-label="复制成功！"></i></span></p><p><span>许可协议:</span><i class="fa 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