layout | title | date | author | summary | references | weight | |||
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notes |
19.Population Activity |
2016-09-30 |
OctoMiao |
Integral equations for population activity |
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19 |
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From equations
$$ \begin{equation}\partial_t p(u,t)= \cdots + A(t)\delta(u-u_r)\end{equation} $$
We integrate over a range of potential
$$\begin{equation} \partial_t \int_{u_1}^{u_2} p(u,t) = \cdots + A(t), \end{equation}$$
provided that
$u_r$ is within$[u_1,u_2]$ .So it's some kind of flux. It works as a source term of faction of neurons at
$u=u_r$ , which is identical to fraction of neurons that spiked per unit time. -
In fact, we have
$$ \begin{equation} A(t) = J(\theta,t) \end{equation} $$
calculates the probability of finding spikes during time interval
Meanwhile we have this survival probability
or identically
What we need for a complete description of network activities is to calculate
Using whatever we have up to this point, the procedure should be
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Apply
$A(t)$ and$I^{\mathrm{ext}}(t)$ to equation (6.8). Within a small time interval$\Delta t$ , we obtain the PSP potential, i.e.,$$ h_{\mathrm{PSP}}(t + \Delta t\vert \hat t) = J_0 \int_0^\infty \epsilon(t - \hat t, s) A(t - s) ds + \int_0^\infty \kappa(t-\hat t,s) I^{\mathrm{ext}}(t-s) ds $$
My thought is, calculating next step is impossible, since we have an integral to infinity? I do not really get it.
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The ultimate reason is that we have insufficient equations compared to the unknown quantities. Unknown:
$A(t)$ ,$h_{\mathrm{PSP}}$ , but we have only one equation.Question: What about other equation? Eqn (6.21), one equation, two variables. Same fate.
So we need another equation. What we get is
Oh wait, new function
Eq. 6.78, 6.79, 6.80
Wilson-Cowan integral form
where
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$f[h(t)]$ rate of firing for a neuron that is not refractory, - given the togal input potential
$h(t)$ .
Constant input potential
To solve the population activity for homogeneous, isotropic and stationary network, all we need is the property of single neuron.
Remove the integral.