{leetcode}/problems/wiggle-sort-ii/[LeetCode - Wiggle Sort II^]
思考题:
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排序再穿插,这个再思考一下?
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找中位数然后索引映射的解法再学习一下。
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{leetcode}/problems/wiggle-sort-ii/discuss/77677/O(n)%2BO(1)-after-median-Virtual-Indexing[O(n)+O(1) after median --- Virtual Indexing - LeetCode Discuss^]
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{leetcode}/problems/wiggle-sort-ii/discuss/77682/Step-by-step-explanation-of-index-mapping-in-Java[Step by step explanation of index mapping in Java - LeetCode Discuss^]
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一步一步将时间复杂度从O(NlogN)降到O(N),将空间复杂度从O(N)降低到O(1) - 摆动排序 II - 力扣(LeetCode)
Given an unsorted array nums
, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]…
.
Example 1:
Input:nums = [1, 5, 1, 1, 6, 4]
Output: One possible answer is[1, 4, 1, 5, 1, 6]
.
Example 2:
Input:nums = [1, 3, 2, 2, 3, 1]
Output: One possible answer is[2, 3, 1, 3, 1, 2]
.
Note:
You may assume all input has valid answer.
Follow Up:
Can you do it in O(n) time and/or in-place with O(1) extra space?
link:{sourcedir}/_0324_WiggleSortII.java[role=include]